I need counter 4-bit please help me

hi
I need counter 4-bit with up count and down count in myhdl and convert to verilog or vhdl.
please help me

Hi,
To get help, you need to provide detailed information. Do you have a sample design to submit ?

#I wrote this program but I don’t know where I’m wrong

from myhdl import *

ACTIVE, INACTIVE = bool(0), bool(1)

DOWN,UP, stop, clk , q = [Signal(INACTIVE) for i in range(5)]

DirType = enum(‘UP’, ‘DOWN’)

def counter(DOWN,UP, stop, clk, q):

I/O pins:
--------

clk      : input free-running clock 
goDown   : input signal to down (active-low switch)
goUp     : input signal to up (active-low switch)
stop     : input signal to stop counting (active-low switch)
q        : 4-bit counter output 



@instance
def logic():
    dir = DirType.__reduce__
    run = False
    while True:
        yield clk.posedge
        # direction
        if UP == ACTIVE:
            dir = DirType.__init__
            run = True
        elif DOWN == ACTIVE:
            dir = DirType.__reduce__
            run = True
        # stop
        if stop == ACTIVE:
            run = False
        # counter action
        if run:
            if dir == DirType.__reduce:
                q.next = q-1 
                
           
            else :       
               q.next = q+1 
             

return logic

counter = counter(DOWN,UP, stop, clk, q)
counter.convert(hdl=“Verilog”, initial_values=True)

And also this app:
from random import randrange
from myhdl import *

ACTIVE_LOW, INACTIVE_HIGH = 0, 1

def Inc(count, down, enable, clock, reset):

@always_seq(clock.posedge, reset=reset)
def incLogic():
    if enable:
        count.next = count+1
    if down:
        count.next = count-1 

return incLogic

conversion

m = 4

count = Signal(modbv(0)[m:])
down = Signal(bool(0))
enable = Signal(bool(0))
clock = Signal(bool(0))
reset = ResetSignal(0, active=0, isasync=True)
n=Signal(modbv(0)[3:])

counter_verilog = inc(count, down, enable, clock, reset)
counter_verilog.convert(hdl=“Verilog”, initial_values=True)

I want to count from (0000) to (1111)
with up count and down count

So what happens when you run it? I assume you’ve written some kind of test to exercise it?

Also, I suggest working a bit more on your code formatting on discourse, which is a little hard to read.

It generally does not convert to vhdl or verilog.

If you can, send me the counter code.

There are two adder designs with test code here https://rosettacode.org/wiki/Four_bit_adder#MyHDL perhaps you could base your work on one of these?